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(B) The energy required to remove an electron from a singly ionized Helium atom $(He^+)$ is given by the formula $E = 13.6 	imes Z^2 / n^2$ eV.For $H

Vedclass · Accepted Answer

$79$

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(B) The energy required to remove an electron from a singly ionized Helium atom $(He^+)$ is given by the formula $E = 13.6 	imes Z^2 / n^2$ eV.For $He^+$,$Z = 2$ and $n = 1$,so $E_1 = 13.6 	imes 2^2 / 1^2 = 54.4$ eV.Let the energy required to remove the first electron from a neutral Helium atom be $x$ eV.According to the problem,$54.4 = 2.2 	imes x$.Solving for $x$,we get $x = 54.4 / 2.2 \approx 24.73$ eV.The total energy required to ionize the Helium atom completely is the sum of the energy to remove the first electron and the energy to remove the second electron from the resulting $He^+$ ion.Total Energy $= x + 54.4 = 24.73 + 54.4 = 79.13$ eV.Rounding to the nearest integer,we get $79$ eV.

The energy required to remove the electron from a singly ionized Helium atom is $2.2$ times the energy required to remove an electron from a Helium atom. The total energy required to ionize the Helium atom completely is......$eV$

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