The kinetic energy of an electron in the n^{t | vedclass

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(D) In the Bohr model of an atom,the total energy $(E)$,kinetic energy $(K)$,and potential energy $(U)$ of an electron in the $n^{th}$ orbit are relat

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$-27.2 \frac{Z^2}{n^2} \ eV$

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(D) In the Bohr model of an atom,the total energy $(E)$,kinetic energy $(K)$,and potential energy $(U)$ of an electron in the $n^{th}$ orbit are related as follows:$K = -E$$U = 2E$Given that the kinetic energy $K = 13.6 \frac{Z^2}{n^2} \ eV$.Since $K = -E$,the total energy $E = -13.6 \frac{Z^2}{n^2} \ eV$.The potential energy $U$ is given by $U = 2E$.Substituting the value of $E$:$U = 2 	imes (-13.6 \frac{Z^2}{n^2} \ eV) = -27.2 \frac{Z^2}{n^2} \ eV$.Therefore,the potential energy is $-27.2 \frac{Z^2}{n^2} \ eV$.

The kinetic energy of an electron in the $n^{th}$ orbit of a hydrogen-like species with atomic number $Z$ is $13.6 \frac{Z^2}{n^2} \ eV$. The potential energy of this electron in the same orbit will be:

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