An organic compound contains C,H,and O in the | vedclass

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(A) Step $1$: Calculate the empirical formula. ElementMass RatioMoles (Mass/Atomic Mass)Simple Ratio$C$$6$$6/12 = 0.5$$0.5/0.5 = 1$$H$$1$$1/1 = 1$$1/0

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$C_2H_4O_2$

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(A) Step $1$: Calculate the empirical formula. ElementMass RatioMoles (Mass/Atomic Mass)Simple Ratio$C$$6$$6/12 = 0.5$$0.5/0.5 = 1$$H$$1$$1/1 = 1$$1/0.5 = 2$$O$$8$$8/16 = 0.5$$0.5/0.5 = 1$Thus,the empirical formula is $CH_2O$. Step $2$: Calculate the empirical formula mass. Empirical formula mass = $(1 	imes 12) + (2 	imes 1) + (1 	imes 16) = 30 \ g/mol$. Step $3$: Calculate the molecular mass. Molecular mass = $2 	imes$ Vapour Density = $2 	imes 30 = 60 \ g/mol$. Step $4$: Calculate the molecular formula. $n = \frac{	ext{Molecular mass}}{	ext{Empirical formula mass}} = \frac{60}{30} = 2$. Molecular formula = $n 	imes (CH_2O) = 2 	imes (CH_2O) = C_2H_4O_2$.

An organic compound contains $C$,$H$,and $O$ in the proportion of $6 : 1 : 8$ by weight,respectively. Its vapour density is $30$. Its molecular formula will be

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