The electronic configuration of elements A, B | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The elements $A, B$ and $C$ belong to Group $1$ (alkali metals) with configurations $[He] 2s^1$ $(Li)$,$[Ne] 3s^1$ $(Na)$ and $[Ar] 4s^1$ $(K)$.As

Vedclass · Accepted Answer

$A > B > C$

Vedclass · Answer

(A) The elements $A, B$ and $C$ belong to Group $1$ (alkali metals) with configurations $[He] 2s^1$ $(Li)$,$[Ne] 3s^1$ $(Na)$ and $[Ar] 4s^1$ $(K)$.As we move down the group,the atomic size increases due to the addition of new shells.An increase in atomic size leads to a decrease in the effective nuclear attraction on the valence electron.Therefore,the energy required to remove the valence electron (first ionization potential) decreases as we move down the group.The order of ionization potential is $A > B > C$.

$I.E.$	$1^{st}$	$2^{nd}$	$3^{rd}$	$4^{th}$	$5^{th}$
Value	$577.5$	$1810$	$2750$	$11580$	$14820$

The electronic configuration of elements $A, B$ and $C$ are $[He] 2s^1, [Ne] 3s^1$ and $[Ar] 4s^1$ respectively. Which one of the following orders is correct for the first ionization potentials (in $kJ \ mol^{-1}$) of $A, B$ and $C$?

Similar Questions

For one of the elements,various successive ionization enthalpies (in $kJ \cdot mol^{-1}$) are given below:

$I.E.$ $1^{st}$ $2^{nd}$ $3^{rd}$ $4^{th}$ $5^{th}$

Value $577.5$ $1810$ $2750$ $11580$ $14820$

The element is:

The correct values of ionization enthalpies (in $kJ \ mol^{-1}$) of $Si, P, Cl$ and $S$ respectively are

Element having highest $I.P.$ value is

Which one of the following is the correct order of the second ionisation potential of $Na$,$Ne$,$Mg$,and $Al$?

The first ionisation energies of alkaline earth metals are higher than those of the alkali metals. This is because

Vedclass Test Series

Exam Paper Generator

Online Exam Module