The electronic configuration of a metal ion i | vedclass

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Question

(A) The condition $\Delta_o < P$ indicates that the complex is a high-spin complex.In a high-spin octahedral complex,the crystal field splitting energ

Vedclass · Accepted Answer

$(t_{2g})^3 (e_g)^1$

Vedclass · Answer

(A) The condition $\Delta_o In a high-spin octahedral complex,the crystal field splitting energy $\Delta_o$ is less than the pairing energy $P$.Therefore,the electrons will occupy the higher energy $e_g$ orbitals before pairing in the lower energy $t_{2g}$ orbitals.For a $d^4$ configuration,the first three electrons will occupy the $t_{2g}$ orbitals singly.The fourth electron will enter the $e_g$ orbital instead of pairing in the $t_{2g}$ orbital because $\Delta_o Thus,the distribution is $(t_{2g})^3 (e_g)^1$.

The electronic configuration of a metal ion in its complex is $[Ar] 3d^4$. For this metal complex,$\Delta_o < P$ ($P=$ energy required for electron pairing in a single orbital). The distribution of electrons in the complex is:

Similar Questions

The degeneracy of $d-$orbitals is lost under:
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