The electric potential at the surface of an atomic nucleus $(Z=50)$ of radius $9 \times 10^{-13} \text{ cm}$ is . . . . . . $\times 10^6 \text{ V}$.

If the radius of the $_{13}^{27}Al$ nucleus is estimated to be $3.6 \, \text{Fermi}$, then the radius of the $_{52}^{125}Te$ nucleus will be nearly .......... $\text{Fermi}$.

The nucleus of an atom with an atomic mass of $24$ and atomic number $11$ consists of:

The mass number of $He$ is $4$ and that for sulphur is $32$. The radius of the sulphur nucleus is larger than that of the helium nucleus by a factor of:

Given below are three schematic graphs of potential energy $V(r)$ versus distance $r$ for three atomic particles: electron $(e^{-})$,proton $(p^{+})$,and neutron $(n)$,in the presence of a nucleus at the origin $O$. The radius of the nucleus is $r_0$. The scale on the $V$-axis may not be the same for all figures. The correct pairing of each graph with the corresponding atomic particle is

$A$ reaction between a proton and $_8^{18}O$ that produces $_9^{18}F$ must also liberate: