The electric field intensity at a point in vacuum is equal to

  • A
    Zero
  • B
    Force a proton would experience there
  • C
    Force an electron would experience there
  • D
    Force a unit positive charge would experience there

Explore More

Similar Questions

Equal charges $q$ are placed at the vertices $A$ and $B$ of an equilateral triangle $ABC$ of side $a$. The magnitude of the electric field at point $C$ is:

Calculate the electric field at the origin due to an infinite number of charges as shown in the figure.

Difficult
View Solution

Electric field in a certain region is given by $\overrightarrow{E} = (\frac{A}{x^2} \hat{i} + \frac{B}{y^3} \hat{j})$. The $SI$ units of $A$ and $B$ are:

The electric field at the center of a semi-circle of radius $a$ and linear charge density $\lambda$ is given by:

Difficult
View Solution

Two charges $Q$ and $4Q$ are separated by a distance of $6 \text{ cm}$. The distance of the point from $4Q$ at which the net electric field is zero is: (in $\text{ cm}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo