The electric field at point $p$ due to an electric dipole is $E$. The electric field at point $R$ on the equatorial line will be $\frac{E}{x}$. The value of $x$ is:

An electric dipole when placed in a uniform electric field $E$ will have minimum potential energy,if the positive direction of dipole moment makes the following angle with $E$.

Three point charges $q, -2q$ and $q$ are placed along the $x$-axis at $x = -a, 0$ and $a$ respectively. As $a \rightarrow 0$ and $q \rightarrow \infty$ while $qa^2 = Q$ remains finite,the electric field at a point $P$,at a distance $x$ $(x \gg a)$ from $x = 0$ is $E = \frac{\alpha Q}{4 \pi \epsilon_0 x^\beta} \hat{i}$. Then:

The electric dipole moment of a short electric dipole is $p$. The electric potential at a point at a distance $r$ from its center and making an angle $\theta$ with the axis of the dipole is .......

Two point charges $+q$ and $-q$ are held fixed at $(-d, 0)$ and $(+d, 0)$ respectively of an $(x, y)$ coordinate system. Then:

If the electric field at a distance $x$ on the axis of an electric dipole is equal to the electric field at a distance $y$ on its equatorial line,what is the ratio $x : y$?