Two point charges +q and -q are held fixed at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The system forms an electric dipole with charges $+q$ at $(-d, 0)$ and $-q$ at $(+d, 0)$.$1$. For points on the $y$-axis,the electric field due to

Vedclass · Accepted Answer

$E$ at all points on the $y$-axis is along $-\hat{i}$

Vedclass · Answer

(A) The system forms an electric dipole with charges $+q$ at $(-d, 0)$ and $-q$ at $(+d, 0)$.$1$. For points on the $y$-axis,the electric field due to the dipole is directed from the positive charge to the negative charge,which is in the $-\hat{i}$ direction.$2$. For points on the $x$-axis,the direction of the electric field changes depending on the position relative to the charges.$3$. The dipole moment $\vec{p}$ is directed from $-q$ to $+q$,which is from $(+d, 0)$ to $(-d, 0)$,i.e.,in the $-\hat{i}$ direction. Its magnitude is $p = q(2d) = 2qd$.$4$. The electric potential $V$ at the origin $(0, 0)$ is $V = \frac{kq}{d} + \frac{k(-q)}{d} = 0$. Since the potential at the origin is zero,the work done to bring a test charge from infinity to the origin is $W = q_0 \Delta V = q_0(0 - 0) = 0$.

Two point charges $+q$ and $-q$ are held fixed at $(-d, 0)$ and $(+d, 0)$ respectively of an $(x, y)$ coordinate system. Then:

Similar Questions

In the situation shown in the diagram,if $q \ll |Q|$ and $r \gg a$,find the net force on the free charge $-q$ and the net torque on it about $O$ at the instant shown. ($p = 2aQ$ is the dipole moment).

Obtain the expression for the electric field due to an electric dipole at a point on its axial line.

Three identical small electric dipoles are arranged parallel to each other at equal separation $a$ as shown in the figure. Their total interaction energy is $U$. Now,one of the end dipoles is gradually reversed. How much work is done by the electric forces?

What is the force acting on an electric dipole in a uniform electric field?

Three identical dipoles are arranged as shown below. What will be the net electric field at $P$ $\left( {k = \frac{1}{{4\pi {\varepsilon _0}}}} \right)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module