The efficiency of a Carnot engine when the so | vedclass

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Question

(A) The efficiency $(\eta)$ of a Carnot engine is defined as the ratio of the work done by the engine to the heat absorbed from the source.For a rever

Vedclass · Accepted Answer

$\frac{T_1 - T_2}{T_1}$

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(A) The efficiency $(\eta)$ of a Carnot engine is defined as the ratio of the work done by the engine to the heat absorbed from the source.For a reversible Carnot cycle,the efficiency depends only on the temperatures of the source and the sink.The formula for the efficiency of a Carnot engine is given by:$\eta = 1 - \frac{T_2}{T_1} = \frac{T_1 - T_2}{T_1}$Where:$T_1$ is the absolute temperature of the source (in Kelvin).$T_2$ is the absolute temperature of the sink (in Kelvin).Therefore,the correct option is $A$.

The efficiency of a Carnot engine when the source temperature is $T_1$ and the sink temperature is $T_2$ is given by:

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