(D) The efficiency $\eta$ of a Carnot engine is given by $\eta = 1 - \frac{T_L}{T_H}$.Here,$T_H = 227 + 273 = 500\, \text{K}$ and $T_L = 127 + 273 = 4

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(D) The efficiency $\eta$ of a Carnot engine is given by $\eta = 1 - \frac{T_L}{T_H}$.Here,$T_H = 227 + 273 = 500\, \text{K}$ and $T_L = 127 + 273 = 400\, \text{K}$.$\eta = 1 - \frac{400}{500} = 1 - 0.8 = 0.2$.Efficiency is also defined as $\eta = \frac{W}{Q_H}$,where $W$ is the work done and $Q_H$ is the heat absorbed at the higher temperature.Given $Q_H = 6 \times 10^4\, \text{cal}$.$W = \eta \times Q_H = 0.2 \times 6 \times 10^4\, \text{cal} = 1.2 \times 10^4\, \text{cal}$.

Class 11 Physics Thermodynamics Heat Engine and Carnot Cycle

Difficult

An ideal heat engine operates on a Carnot cycle between $227\,^{\circ}C$ and $127\,^{\circ}C$. It absorbs $6 \times 10^4\, \text{cal}$ at the higher temperature. The amount of heat converted into work is equal to:

A
$4.8 \times 10^4\, \text{cal}$
B
$3.5 \times 10^4\, \text{cal}$
C
$1.6 \times 10^4\, \text{cal}$
D
$1.2 \times 10^4\, \text{cal}$

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Heat Engine and Carnot Cycle

$A$ diatomic gas is used in a Carnot heat engine. If the efficiency of the given Carnot heat engine is $80\%$,then find the ratio of the initial volume to the final volume of the gas during adiabatic expansion.

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$A$ Carnot engine has the same efficiency between $(i)$ $100 \ K$ and $600 \ K$ and (ii) $T \ K$ and $960 \ K$. The temperature $T$ in kelvin of the sink is

DifficultMHT CET 2023

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$A$ Carnot engine operating between temperatures $600 \,K$ and $300 \,K$ absorbs $800 \,J$ of heat from the source. The mechanical work done per cycle is (in $\,J$)

EasyAP EAMCET 2022

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$A$ scientist claims that the efficiency of their heat engine,which operates between a source temperature of $127^{\circ}C$ and a sink temperature of $27^{\circ}C$,is $26\%$. Then:

MediumAIPMT 2001

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Determine the efficiency of a Carnot cycle if,in the adiabatic expansion,the volume becomes $3$ times its initial value and $\gamma = 1.5$.

MediumAIIMS 2019

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An ideal heat engine operates on a Carnot cycle between $227\,^{\circ}C$ and $127\,^{\circ}C$. It absorbs $6 \times 10^4\, \text{cal}$ at the higher temperature. The amount of heat converted into work is equal to:

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$A$ diatomic gas is used in a Carnot heat engine. If the efficiency of the given Carnot heat engine is $80\%$,then find the ratio of the initial volume to the final volume of the gas during adiabatic expansion.

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