The efficiency of a Carnot heat engine:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The efficiency of a Carnot heat engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$.Here,$T_1$ is the temperature of the source (hot rese

Vedclass · Accepted Answer

is independent of the working substance

Vedclass · Answer

(B) The efficiency of a Carnot heat engine is given by the formula: $\eta = 1 - \frac{T_2}{T_1}$.Here,$T_1$ is the temperature of the source (hot reservoir) and $T_2$ is the temperature of the sink (cold reservoir).From this expression,it is clear that the efficiency depends solely on the temperatures of the source and the sink.It is independent of the nature of the working substance used in the engine.Therefore,option $B$ is the correct statement.

Similar Questions

An engine has an efficiency of $1/6$. When the temperature of the sink is reduced by $62^{\circ}C$,its efficiency is doubled. The temperature of the source is ....... $^{\circ}C$.

Who first proposed (invented) the Carnot engine?

State Carnot's theorem.

$300 \, cal$ of heat is given to a heat engine and it rejects $225 \, cal$ of heat. If the source temperature is $227^{\circ} C$,then the temperature of the sink will be . . . . . . $^{\circ} C$.

$A$ Carnot engine has an efficiency of $\frac{1}{6}$. When the temperature of the sink is lowered by $57 \ K$,its efficiency becomes $\frac{1}{3}$. The temperature of the source is: (in $K$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module