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(D) Let the resistance of each wire be $R$. Since all four wires have equal length,equal area of cross-section,and are made of the same material,their

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$4$

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(D) Let the resistance of each wire be $R$. Since all four wires have equal length,equal area of cross-section,and are made of the same material,their resistances are identical.When $n$ identical resistors are connected in parallel,the equivalent resistance $R_p$ is given by $R_p = \frac{R}{n}$.Given $n = 4$ and $R_p = 0.25\, \Omega$,we have $0.25 = \frac{R}{4}$,which implies $R = 0.25 	imes 4 = 1\, \Omega$.When these four resistors are connected in series,the equivalent resistance $R_s$ is given by $R_s = n 	imes R$.Therefore,$R_s = 4 	imes 1 = 4\, \Omega$.

The effective resistance of a parallel connection that consists of four wires of equal length,equal area of cross-section,and same material is $0.25\, \Omega$. What will be the effective resistance if they are connected in series? (In $\Omega$)

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