The eccentricity of the ellipse 9{x^2} + 5{y^ | vedclass

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Question

(b) $9{x^2} + {(\sqrt 5 y - 3\sqrt 5 )^2} = 45$ or $\frac{{{x^2}}}{5} + \frac{{{{(y - 3)}^2}}}{9} = 0$

==> ${a^2} = 5,$ ${b^2} = 9$.

Therefor

Vedclass · Accepted Answer

$2\over3$

Vedclass · Answer

(b) $9{x^2} + {(\sqrt 5 y - 3\sqrt 5 )^2} = 45$ or $\frac{{{x^2}}}{5} + \frac{{{{(y - 3)}^2}}}{9} = 0$

==> ${a^2} = 5,$ ${b^2} = 9$.

Therefore $e = \frac{2}{3}$.

The eccentricity of the ellipse $9{x^2} + 5{y^2} - 30y = 0$, is

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