The distance between the vertex and the focus of the parabola $x^2-2x+3y-2=0$ is

  • A
    $\frac{4}{5}$
  • B
    $\frac{3}{4}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{5}{6}$

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Let $A$ be the focus of the parabola $y^{2}=8x$. Let the line $y=mx+c$ intersect the parabola at two distinct points $B$ and $C$. If the centroid of the triangle $ABC$ is $(\frac{7}{3},\frac{4}{3})$,then $(BC)^{2}$ is equal to:

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