The distance between the points A(-4, -6) and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $A(-

Vedclass · Accepted Answer

$-6$

Vedclass · Answer

(C) The distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $A(-4, -6)$ and $B(6, b)$ with distance $d = 10$.Substituting the values into the formula:$10 = \sqrt{(6 - (-4))^2 + (b - (-6))^2}$$10 = \sqrt{(6 + 4)^2 + (b + 6)^2}$$10 = \sqrt{10^2 + (b + 6)^2}$Squaring both sides:$100 = 100 + (b + 6)^2$$(b + 6)^2 = 100 - 100$$(b + 6)^2 = 0$Taking the square root of both sides:$b + 6 = 0$$b = -6$.

The distance between the points $A(-4, -6)$ and $B(6, b)$ is $10,$ then $b = \dots$

Similar Questions

Prove that $(2a, 4a)$, $(2a, 6a)$, and $(2a + \sqrt{3}a, 5a)$ are the vertices of an equilateral triangle.

Find the point on the $X$-axis which is equidistant from $(5, 4)$ and $(-2, 3)$.

State whether the following statements are true or false. Justify your answer.
The points $(0,5), (0,-9)$ and $(3,6)$ are collinear.

Using the distance formula,show that the points $(0, -3), (1, -1),$ and $(2, 1)$ are collinear.

If the distance between the points $(2, -3)$ and $(5, b)$ is $5,$ then $b = \ldots \ldots \ldots .$

Vedclass Test Series

Exam Paper Generator

Online Exam Module