The displacement-time graph for two particles | vedclass

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(D) The velocity of a particle in a displacement-time graph is given by the slope of the line,which is $	an 	heta$,where $	heta$ is the angle the l

Vedclass · Accepted Answer

$1:3$

Vedclass · Answer

(D) The velocity of a particle in a displacement-time graph is given by the slope of the line,which is $	an 	heta$,where $	heta$ is the angle the line makes with the time axis.For particle $A$,the angle is $	heta_A = 30^\circ$,so $V_A = 	an 30^\circ = 1/\sqrt{3}$.For particle $B$,the angle is $	heta_B = 60^\circ$,so $V_B = 	an 60^\circ = \sqrt{3}$.The ratio of velocities is $\frac{V_A}{V_B} = \frac{	an 30^\circ}{	an 60^\circ} = \frac{1/\sqrt{3}}{\sqrt{3}} = \frac{1}{3}$.Therefore,the ratio $V_A:V_B$ is $1:3$.

The displacement-time graph for two particles $A$ and $B$ are straight lines inclined at angles of $30^\circ$ and $60^\circ$ with the time axis. The ratio of velocities $V_A:V_B$ is

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