The direct current which would give the same heating effect in an equal constant resistance as the current shown in figure, i.e. the $r.m.s.$ current, is.....$A$
$0$
$\sqrt 2$
$2$
$2 \sqrt 2 $
The voltage of an ac source varies with time according to the equation $V = 100\sin \;100\pi t\,\cos \,100\pi t$ where $t$ is in seconds and $V$ is in volts. Then
An $AC$ current is given by $I = I _{1} \sin \omega t + I _{2} \cos \omega t$. A hot wire ammeter will give a reading
The peak value of an Alternating current is $ 6$ amp, then r.m.s. value of current will be
A resistance of $40 \,\Omega$ is connected to a source of alternating current rated $220\, V , 50 Hz$. Find the time taken by the current to change from its maximum value to $ms$ value
The peak voltage of the ac source is equal to: