The dimensions of permeability of free space | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The force per unit length $(F/l)$ between two parallel current-carrying conductors is given by the formula:$F/l = \frac{\mu_0}{4\pi} \frac{2I_1 I_

Vedclass · Accepted Answer

$[MLT^{-2} A^{-2}]$

Vedclass · Answer

(A) The force per unit length $(F/l)$ between two parallel current-carrying conductors is given by the formula:$F/l = \frac{\mu_0}{4\pi} \frac{2I_1 I_2}{d}$Rearranging for $\mu_0$:$\mu_0 = \frac{F \cdot d}{l \cdot 2I_1 I_2}$Substituting the dimensions:$[F] = [MLT^{-2}]$$[d] = [L]$$[l] = [L]$$[I] = [A]$$[\mu_0] = \frac{[MLT^{-2}] \cdot [L]}{[L] \cdot [A]^2} = [MLT^{-2} A^{-2}]$Thus, the dimensions of permeability of free space are $[MLT^{-2} A^{-2}]$.

The dimensions of permeability of free space $(\mu_0)$ can be given by:

Similar Questions

The magnetic moment has dimensions of

The dimensional formula of permeability of free space $\mu_0$ is

In $SI$ units,$kg m^2 s^{-2}$ is equivalent to which of the following?

The dimensional formula of farad is

What is the spring constant of a spring? Write its unit and dimensional formula.

Vedclass Test Series

Exam Paper Generator

Online Exam Module