The dimensional formula of farad is

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Question

(A) The capacitance $C$ is defined as $C = \frac{Q}{V}$,where $Q$ is charge and $V$ is potential difference.Since potential difference $V = \frac{W}{Q

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$[M^{-1}L^{-2}T^2Q^2]$

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(A) The capacitance $C$ is defined as $C = \frac{Q}{V}$,where $Q$ is charge and $V$ is potential difference.Since potential difference $V = \frac{W}{Q}$,where $W$ is work done,we can write $C = \frac{Q^2}{W}$.The dimensional formula for work $W$ is $[ML^2T^{-2}]$.Substituting the dimensions,we get $[C] = \frac{[Q^2]}{[ML^2T^{-2}]}$.Therefore,$[C] = [M^{-1}L^{-2}T^2Q^2]$.

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