The dimensional formula of current sensitivity of a moving coil galvanometer is

$A$ rectangular coil of effective area $0.05 \ m^2$ is suspended freely in a radial magnetic field of $0.01 \ Wb/m^2$. The torsional constant of the suspension fiber is $5 \times 10^{-9} \ Nm/\text{degree}$. If a current of $300 \ \mu A$ is passed through it,then the angle through which the coil rotates is (in $^{\circ}$)

$A$ galvanometer has a resistance of $7\,\Omega$ and gives a full-scale deflection for a current of $1.0\,A$. How will you convert it into a voltmeter of range $10\,V$?

$A$ galvanometer coil has a resistance $80 \Omega$ and current for full-scale deflection is $10 \text{ mA}$. $A$ resistance of $920 \Omega$ is connected in series with the galvanometer to make a voltmeter. If the least count of the voltmeter is $0.2 \text{ V}$,the number of divisions on the scale is:

If an ammeter is to be used in place of a galvanometer,then we must connect:

Two galvanometers $G_{1}$ and $G_{2}$ require $2 \ mA$ and $3 \ mA$ respectively to produce the same deflection. Then: