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(C) The induced electromotive force $(e_{2})$ in a secondary coil is given by the formula: $e_{2} = -M \frac{di_{1}}{dt}$.Here,$M$ is the mutual induc

Vedclass · Accepted Answer

$[ML^{2}T^{-2}A^{-2}]$

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(C) The induced electromotive force $(e_{2})$ in a secondary coil is given by the formula: $e_{2} = -M \frac{di_{1}}{dt}$.Here,$M$ is the mutual inductance and $i_{1}$ is the current in the primary coil.Rearranging for $M$,we get: $M = -\frac{e_{2}}{di_{1}/dt}$.The dimensional formula for induced emf $(e_{2})$ is the same as potential difference,which is $[ML^{2}T^{-3}A^{-1}]$.The dimensional formula for the rate of change of current $(di_{1}/dt)$ is $[AT^{-1}]$.Therefore,the dimension of $M$ is: $[M] = \frac{[ML^{2}T^{-3}A^{-1}]}{[AT^{-1}]} = [ML^{2}T^{-2}A^{-2}]$.

The dimension of mutual inductance is ............

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