The difference between simple interest and co | vedclass

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Question

Let the sum be $P$.

$P\left[\left(1+\frac{4}{100}ight)^{2}-1ight]-P 	imes \frac{2 	imes 4}{100}=1$

$P\left[\left(\frac{26}{25}ight)^{2}-

Vedclass · Accepted Answer

$625$

Vedclass · Answer

Let the sum be $P$.

$P\left[\left(1+\frac{4}{100}ight)^{2}-1ight]-P 	imes \frac{2 	imes 4}{100}=1$

$P\left[\left(\frac{26}{25}ight)^{2}-1-\frac{2}{25}ight]=1$

$P=\frac{1 	imes(25)^{2}}{(26)^{2}-(25)^{2}-50}=\frac{(25)^{2}}{(51) 1-50}=(25)^{2}=₹ 625$

The difference between simple interest and compound interest compounded annually on a certain sum of money for $2$ years at $4 \%$ per annum is ₹ $1 .$ The sum (in ₹) is

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