(B) Let the integer be $x$. The expression is $x - x^3 = x(1 - x^2) = x(1 - x)(1 + x) = (x - 1)(x)(x + 1)$. This is the product of three consecutive i

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(B) Let the integer be $x$. The expression is $x - x^3 = x(1 - x^2) = x(1 - x)(1 + x) = (x - 1)(x)(x + 1)$. This is the product of three consecutive integers. The product of $n$ consecutive integers is always divisible by $n!$. Therefore,the product of $3$ consecutive integers is divisible by $3! = 3 \times 2 \times 1 = 6$.