The diameter of a sphere is measured using a vernier caliper whose $9$ divisions of main scale are equal to $10$ divisions of vernier scale. The shortest division on the main scale is equal to $1 \mathrm{~mm}$. The main scale reading is $2 \mathrm{~cm}$ and second division of vernier scale coincides with a division on main scale. If mass of the sphere is $8.635 \mathrm{~g}$, thedensity of the sphere $1 \mathrm{~s}$ :
The diameter of a sphere is measured using a vernier caliper whose $9$ divisions of main scale are equal to $10$ divisions of vernier scale. The shortest division on the main scale is equal to $1 \mathrm{~mm}$. The main scale reading is $2 \mathrm{~cm}$ and second division of vernier scale coincides with a division on main scale. If mass of the sphere is $8.635 \mathrm{~g}$, thedensity of the sphere $1 \mathrm{~s}$ :
- [JEE MAIN 2024]
- A
$2.5 \mathrm{~g} / \mathrm{cm}^3$
- B
$1.7 \mathrm{~g} / \mathrm{cm}^3$
- C
$2.2 \mathrm{~g} / \mathrm{cm}^3$
- D
$2.0 \mathrm{~g} / \mathrm{cm}^3$
Similar Questions
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Main scale reading : $0 \,\mathrm{~mm}$
Circular scale reading $: 52$ $divisions$
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- [NEET 2021]
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- [JEE MAIN 2019]
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- [JEE MAIN 2021]
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