The diameter of a sphere is measured as $42 \text{ cm}$. If there is an error of $1/77 \text{ cm}$ in measuring it,then the error involved in the volume of that sphere (in cubic centimeters) is

If the percentage error in the radius of a circle is $3\%$,then the percentage error in its area is:

If $y=5x^2+6x+6$,$x=2$,and $\Delta x=0.001$,then the values of $\Delta y$ and $dy$ respectively are:

The circumference of a circle is measured as $56 \text{ cm}$ with an error of $0.02 \text{ cm}$. The percentage error in its area is

For a given function $y=f(x)$,$\delta y$ denotes the actual error in $y$ corresponding to an actual error $\delta x$ in $x$,and $dy$ denotes the approximate value of $\delta y$. If $y=f(x)=2x^2-3x+4$ and $\delta x=0.02$,then the value of $\delta y - dy$ when $x=5$ is

Find the approximate value of $(32.15)^{\frac{1}{5}}$.