The diameter of a metallic ball is 4.2, cm. W | vedclass

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(D) Given: Diameter of the metallic ball $= 4.2\, cm$.Radius $(r) = \frac{4.2}{2}\, cm = 2.1\, cm$.Volume of the spherical ball $= \frac{4}{3} \pi r^3

Vedclass · Accepted Answer

$345.39$

Vedclass · Answer

(D) Given: Diameter of the metallic ball $= 4.2\, cm$.Radius $(r) = \frac{4.2}{2}\, cm = 2.1\, cm$.Volume of the spherical ball $= \frac{4}{3} \pi r^3$.Volume $= \frac{4}{3} 	imes \frac{22}{7} 	imes (2.1)^3\, cm^3 = \frac{4}{3} 	imes \frac{22}{7} 	imes 2.1 	imes 2.1 	imes 2.1\, cm^3$.Volume $= 4 	imes 22 	imes 0.1 	imes 2.1 	imes 2.1\, cm^3 = 38.808\, cm^3$.Density of the metal $= 8.9\, g/cm^3$.Mass of the ball $= 	ext{Density} 	imes 	ext{Volume} = 8.9\, g/cm^3 	imes 38.808\, cm^3$.Mass $= 345.3912\, g \approx 345.39\, g$.Thus,the mass of the ball is $345.39\, g$ (approx.).

The diameter of a metallic ball is $4.2\, cm$. What is the mass of the ball,if the density of the metal is $8.9\, g/cm^3$ (in $, g$)?

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