The diameter of a hemisphere with TSA 462,cm^ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The Total Surface Area $(TSA)$ of a hemisphere is given by the formula: $TSA = 3\pi r^{2}$.Given,$TSA = 462\,cm^{2}$.So,$3\pi r^{2} = 462$.Using $

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(B) The Total Surface Area $(TSA)$ of a hemisphere is given by the formula: $TSA = 3\pi r^{2}$.Given,$TSA = 462\,cm^{2}$.So,$3\pi r^{2} = 462$.Using $\pi = \frac{22}{7}$,we have $3 	imes \frac{22}{7} 	imes r^{2} = 462$.$r^{2} = 462 	imes \frac{7}{3 	imes 22}$.$r^{2} = 462 	imes \frac{7}{66}$.$r^{2} = 7 	imes 7 = 49$.$r = \sqrt{49} = 7\,cm$.The diameter $d = 2r = 2 	imes 7 = 14\,cm$.

The diameter of a hemisphere with $TSA$ $462\,cm^{2}$ is $\ldots \ldots \ldots \,cm$.

Similar Questions

The Curved Surface Area $(CSA)$ of a frustum of a cone is given by:

The ratio of radii of two spheres is $3:2$. Then,the ratio of their surface areas is $\ldots \ldots \ldots \ldots$

The volume of a cone with radius $5 \, cm$ and height $12 \, cm$ is ........ $\pi \, cm^{3}$.

........ is a unit of area.

The $CSA$ (Curved Surface Area) of a $1-$ rupee coin is given by the formula $\ldots \ldots \ldots \ldots .$

Vedclass Test Series

Exam Paper Generator

Online Exam Module