(C) Radius of the garden $r_2 = \frac{\text{diameter}}{2} = \frac{210}{2} = 105 \,m$.Radius of the garden excluding the path $r_1 = 105 - 7 = 98 \,m$.

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(C) Radius of the garden $r_2 = \frac{\text{diameter}}{2} = \frac{210}{2} = 105 \,m$.Radius of the garden excluding the path $r_1 = 105 - 7 = 98 \,m$.Area of the path in the form of a circular ring is given by the difference between the area of the outer circle and the inner circle.Area of the path $= \pi r_2^2 - \pi r_1^2$$= \pi(r_2^2 - r_1^2)$$= \pi(r_2 + r_1)(r_2 - r_1)$$= \frac{22}{7} \times (105 + 98) \times (105 - 98)$$= \frac{22}{7} \times 203 \times 7$$= 22 \times 203$$= 4466 \,m^2$.

Class 10 Mathematics Areas Related to Circles Mix Examples - Areas Related to Circles

Difficult

The diameter of a circular garden is $210 \,m$. Inside it,all along the boundary,there is a path of uniform width $7 \,m$. Then,the area of the path is $\ldots \ldots \ldots \ldots \,m^2$.

A
$2310$
B
$735$
C
$4466$
D
$4455$

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Mix Examples - Areas Related to Circles

It is proposed to build a single circular park equal in area to the sum of areas of two circular parks of diameters $16 \, m$ and $12 \, m$ in a locality. The radius of the new park would be (in $m$)

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The numerical value of the area of a circle is greater than the numerical value of its circumference. Is this statement true? Why?

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Four circular cardboard pieces of radii $7 \, cm$ are placed on a paper in such a way that each piece touches the other two pieces. Find the area of the portion enclosed between these pieces (in $cm^2$).

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The length of the minute hand of a clock is $14 \, cm$. If the minute hand moves from $1$ to $10$ on the dial,then $\ldots \ldots \ldots \ldots \, cm^2$ area will be covered.

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The length of a square field is $50 \, m$. $A$ cow is tethered at one of the vertices by a $3 \, m$ long rope. Find the area of the region of the field in which the cow can graze. $(\pi = 3.14)$ (in $m^2$)

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The diameter of a circular garden is $210 \,m$. Inside it,all along the boundary,there is a path of uniform width $7 \,m$. Then,the area of the path is $\ldots \ldots \ldots \ldots \,m^2$.

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It is proposed to build a single circular park equal in area to the sum of areas of two circular parks of diameters $16 \, m$ and $12 \, m$ in a locality. The radius of the new park would be (in $m$)

The numerical value of the area of a circle is greater than the numerical value of its circumference. Is this statement true? Why?

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