The diagram shows a cup of tea seen from above. The tea has been stirred and is now rotating without turbulence. $A$ graph showing the speed $v$ with which the liquid is crossing points at a distance $X$ from $O$ along a radius $XO$ would look like:

  • A
    Option A
  • B
    Option B
  • C
    Option C
  • D
    Option D

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As shown in the figure,a liquid is at the same level in both arms of a $U$-tube of uniform cross-section when at rest. If the $U$-tube moves with an acceleration '$f$' towards the right,the difference between the liquid heights in the two arms of the $U$-tube will be (acceleration due to gravity $= g$):

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