(N/A) The lens is a convex lens.
Since the image is virtual,erect,and magnified,the object must be placed between the optical center and the focus of the convex lens.
The lens is situated between the object $O$ and the image $I.$
To locate the lens,draw a line from the top of the object to the top of the image and extend it to intersect the principal axis; this point is the optical center of the lens.
Draw a vertical line through this point to represent the lens.
To locate the focus $F,$ draw a ray from the top of the object parallel to the principal axis,which will pass through the focus after refraction. Extend this refracted ray backward to meet the image point. The point where the parallel ray meets the principal axis after refraction is the focus $F.$