(B) The molar volume $V_m$ is calculated as $V_m = \frac{\text{Molar mass}}{\text{density}} = \frac{27}{0.3} = 90 \ L/mol$.The compressibility factor

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$A$ behaves non-ideally with positive deviation

(B) The molar volume $V_m$ is calculated as $V_m = \frac{\text{Molar mass}}{\text{density}} = \frac{27}{0.3} = 90 \ L/mol$.The compressibility factor $Z$ is given by $Z = \frac{P V_m}{R T}$.Using $R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$,we get $Z = \frac{1 \times 90}{0.0821 \times 750} \approx 1.46$.Since $Z > 1$,the gas $A$ shows positive deviation from ideal behavior.

Class 11 Chemistry States of Matter Real gases and Vander waal’s equation

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The density of a gas $A$ at $1 \ atm$ and $750 \ K$ is $0.3 \ g/L$. If the molar mass of $A$ is $27 \ g/mol$,then choose the correct statement -

A
$A$ behaves ideally
B
$A$ behaves non-ideally with positive deviation
C
$A$ behaves non-ideally with negative deviation
D
$A$ can be liquefied by applying pressure at $750 \ K$.

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The density of a gas $A$ at $1 \ atm$ and $750 \ K$ is $0.3 \ g/L$. If the molar mass of $A$ is $27 \ g/mol$,then choose the correct statement -

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