The decreasing order of stability of the foll | vedclass

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Question

(A) The stability of a carbanion is directly proportional to the electron-withdrawing group $(EWG)$ effect and inversely proportional to the electron-

Vedclass · Accepted Answer

$Q > R > S > P$

Vedclass · Answer

(A) The stability of a carbanion is directly proportional to the electron-withdrawing group $(EWG)$ effect and inversely proportional to the electron-releasing group $(ERG)$ effect.In the given anions:$Q$ has a $-CHO$ group,which is a strong $EWG$ ($-M$ effect).$R$ has a $-Cl$ group,which is an $EWG$ ($-I$ effect).$S$ has a $-CH_3$ group,which is an $ERG$ ($+I$ and hyperconjugation).$P$ has a $-OCH_3$ group,which is a strong $ERG$ ($+M$ effect).Therefore,the order of stability is $Q > R > S > P$.

The decreasing order of stability of the following anions is:

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