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(B) According to Ohm's law,$R = \frac{V}{I}$.In the given $I-V$ graph,the slope of the line is $\frac{I}{V} = \frac{1}{R}$.Since the slope of the line

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$T_1 < T_2$

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(B) According to Ohm's law,$R = \frac{V}{I}$.In the given $I-V$ graph,the slope of the line is $\frac{I}{V} = \frac{1}{R}$.Since the slope of the line for $T_1$ is greater than the slope of the line for $T_2$,we have $\frac{1}{R_1} > \frac{1}{R_2}$,which implies $R_1 For a metallic conductor,resistance $R$ increases with an increase in temperature $T$.Since $R_1 < R_2$,it follows that $T_1 < T_2$.

The current in a metallic conductor is plotted against voltage at two different temperatures $T_1$ and $T_2$. Which of the following is correct?

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