Which among the following is true?

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(B) $1$. Option $A$ is incorrect because alloys with low temperature coefficients of resistance (like Manganin or Constantan) are used,not necessarily

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$\vec{E} = \rho \vec{J}$ is the statement of Ohm's law (where $\vec{E}$ is the electric field and $\vec{J}$ is the current density).

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(B) $1$. Option $A$ is incorrect because alloys with low temperature coefficients of resistance (like Manganin or Constantan) are used,not necessarily those with very low resistivity.$2$. Option $B$ is correct. The microscopic form of Ohm's law is given by $\vec{J} = \sigma \vec{E}$,which can be written as $\vec{E} = \rho \vec{J}$,where $\rho$ is resistivity.$3$. Option $C$ is incorrect because $V = IR$ is only valid for Ohmic conductors,not for non-Ohmic materials like semiconductors or diodes.$4$. Therefore,only statement $B$ is true.

$I (A)$	$V (V)$	$I (A)$	$V (V)$
$0.2$	$3.94$	$3.0$	$59.2$
$0.4$	$7.87$	$4.0$	$78.8$
$0.6$	$11.8$	$5.0$	$98.6$
$0.8$	$15.7$	$6.0$	$118.5$
$1.0$	$19.7$	$7.0$	$138.2$
$2.0$	$39.4$	$8.0$	$158.0$

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The variation of current $(i)$ and voltage $(V)$ in a conductor is shown in the diagram below. The resistance of the conductor is ........... $\Omega$.

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What conclusion can you draw from the following observations on a resistor made of alloy manganin?
$I (A)$ $V (V)$ $I (A)$ $V (V)$
$0.2$ $3.94$ $3.0$ $59.2$
$0.4$ $7.87$ $4.0$ $78.8$
$0.6$ $11.8$ $5.0$ $98.6$
$0.8$ $15.7$ $6.0$ $118.5$
$1.0$ $19.7$ $7.0$ $138.2$
$2.0$ $39.4$ $8.0$ $158.0$

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