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(B) The $rms$ value of current is defined as $I_{rms} = \sqrt{\frac{1}{T_2 - T_1} \int_{T_1}^{T_2} I^2 dt}$.Given $I = 2\sqrt{t}$,so $I^2 = 4t$.The in

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$2\sqrt{3} \, A$

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(B) The $rms$ value of current is defined as $I_{rms} = \sqrt{\frac{1}{T_2 - T_1} \int_{T_1}^{T_2} I^2 dt}$.Given $I = 2\sqrt{t}$,so $I^2 = 4t$.The interval is from $T_1 = 2 \, s$ to $T_2 = 4 \, s$,so the duration is $T_2 - T_1 = 4 - 2 = 2 \, s$.Calculating the integral: $\int_{2}^{4} 4t \, dt = [2t^2]_{2}^{4} = 2(4^2 - 2^2) = 2(16 - 4) = 2(12) = 24$.Now,the mean square value is $\langle I^2 angle = \frac{1}{2} 	imes 24 = 12 \, A^2$.Therefore,$I_{rms} = \sqrt{12} = 2\sqrt{3} \, A$.

The current in a circuit varies with time as $I = 2 \sqrt{t}$. The $rms$ value of the current for the interval $t = 2 \, s$ to $t = 4 \, s$ is:

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