The current (I) in an inductor is varying wit | vedclass

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(A) The voltage $(V)$ across an inductor is given by the formula $V = L \frac{dI}{dt}$, where $L$ is the inductance and $\frac{dI}{dt}$ is the rate of

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(A) The voltage $(V)$ across an inductor is given by the formula $V = L \frac{dI}{dt}$, where $L$ is the inductance and $\frac{dI}{dt}$ is the rate of change of current with respect to time.From the graph, the current $(I)$ increases linearly with time $(t)$ for a certain interval, meaning the slope $\frac{dI}{dt}$ is constant and positive.Since $V = L 	imes (	ext{constant})$, the voltage $(V)$ will be a constant positive value during this interval.When the current $(I)$ is constant, $\frac{dI}{dt} = 0$, so the voltage $(V)$ becomes $0$.When the current $(I)$ decreases linearly, the slope $\frac{dI}{dt}$ is constant and negative, so the voltage $(V)$ becomes a constant negative value.Therefore, the graph of voltage $(V)$ versus time $(t)$ will be a series of horizontal steps corresponding to the slopes of the current-time graph.

The current $(I)$ in an inductor is varying with time $(t)$ as shown in the figure. Which of the following graphs shows the correct variation of voltage $(V)$ with time $(t)$ in the inductor?

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