The crystal field stabilization energy of $[Co(NH_3)_6]Cl_3$ is $......... \Delta_0$

Which one of the following statements is correct for $d^4$ ions $(P = \text{pairing energy})$?

The crystal field stabilisation energy of $[Co(NH_3)_6]Cl_3$ is

Crystal field splitting energy $(CFSE)$ for $[CoCl_6]^{4-}$ is $18000 \ cm^{-1}$. The crystal field splitting energy $(CFSE)$ for $[CoCl_4]^{2-}$ will be (in $cm^{-1}$)

Crystal field stabilization energy for high spin $d^4$ octahedral complex is

Arrange the following Cobalt complexes in the order of increasing Crystal Field Stabilization Energy $(CFSE)$ value.
Complexes: $[CoF_{6}]^{3-}, [Co(H_{2}O)_{6}]^{2+}, [Co(NH_{3})_{6}]^{3+}$ and $[Co(en)_{3}]^{3+}$
$A: [CoF_{6}]^{3-}, B: [Co(H_{2}O)_{6}]^{2+}, C: [Co(NH_{3})_{6}]^{3+}, D: [Co(en)_{3}]^{3+}$
Choose the correct option: