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(B) Statement $a$ is correct: Benzene $(C_6H_6)$ has $6$ $C-C$ sigma bonds and $6$ $C-H$ sigma bonds,totaling $12$ sigma bonds.Statement $b$ is incorr

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$a, b$

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(B) Statement $a$ is correct: Benzene $(C_6H_6)$ has $6$ $C-C$ sigma bonds and $6$ $C-H$ sigma bonds,totaling $12$ sigma bonds.Statement $b$ is incorrect: According to Fajan's rule,smaller cations have higher polarizing power. Since $Li^+$ is smaller than $K^+$,$LiF$ has more covalent character than $KF$. Wait,the statement says $LiF$ is more covalent than $KF$,which is correct.Statement $c$ is incorrect: According to Fajan's rule,higher oxidation state of the cation leads to higher covalent character. Therefore,$SnCl_4$ $(Sn^{4+})$ is more covalent than $SnCl_2$ $(Sn^{2+})$.Thus,statements $a$ and $b$ are correct.

List-$I$ (Molecule Species)	List-$II$ (Property/Shape)
$A$. $SO_2Cl_2$	$I$. Paramagnetic
$B$. $NO$	$II$. Diamagnetic
$C$. $NO_2^-$	$III$. Tetrahedral
$D$. $I_3^-$	$IV$. Linear

The correct statements from the following are:
$a$) The total number of sigma bonds present in benzene is $12$
$b$) $LiF$ is more covalent than $KF$
$c$) $SnCl_2$ is more covalent than $SnCl_4$

Similar Questions

Match List-$I$ with List-$II$ :

List-$I$ (Molecule Species) List-$II$ (Property/Shape)

$A$. $SO_2Cl_2$ $I$. Paramagnetic

$B$. $NO$ $II$. Diamagnetic

$C$. $NO_2^-$ $III$. Tetrahedral

$D$. $I_3^-$ $IV$. Linear

Choose the correct answer from the options given below :

Compound $X$ is the anhydride of sulphuric acid. The number of $\sigma$-bonds and the number of $\pi$-bonds present in $X$ are,respectively:

What are the similarities and differences in the Lewis structures of $H_2SO_4$ and $SO_4^{2-}$?

$BCl_3$ does not exist as a dimer,but $BH_3$ exists as a dimer $(B_2H_6)$ because:

The correct order of the $O-O$ bond length in $O_2$,$H_2O_2$,and $O_3$ is:

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The correct statements from the following are:$a$) The total number of sigma bonds present in benzene is $12$$b$) $LiF$ is more covalent than $KF$$c$) $SnCl_2$ is more covalent than $SnCl_4$