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(A) $I$. In the borax bead test,cobalt oxide reacts with $B_2O_3$ to form cobalt metaborate,$Co(BO_2)_2$,which is blue in color. This statement is cor

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$I$ & $II$

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(A) $I$. In the borax bead test,cobalt oxide reacts with $B_2O_3$ to form cobalt metaborate,$Co(BO_2)_2$,which is blue in color. This statement is correct.$II$. Diborane $(B_2H_6)$ is prepared by the reaction of sodium borohydride $(NaBH_4)$ with iodine $(I_2)$: $2NaBH_4 + I_2 \rightarrow B_2H_6 + 2NaI + H_2$. This statement is correct.$III$. In diborane $(B_2H_6)$,boron is more electropositive than hydrogen,so the oxidation state of hydrogen is $-1$. This statement is incorrect.$IV$. Boric acid $(H_3BO_3)$ is a weak monobasic Lewis acid,not a tribasic acid,as it accepts $OH^-$ ions from water. This statement is incorrect.Therefore,statements $I$ and $II$ are correct.

The correct statements about the compounds of boron are:
$I$. In borax bead test,the colour of cobalt metaborate is blue.
$II$. Diborane is prepared by the oxidation of sodium borohydride with iodine.
$III$. In diborane,the oxidation state of hydrogen is $+1$.
$IV$. Boric acid is a tribasic acid.

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The correct statements about the compounds of boron are:$I$. In borax bead test,the colour of cobalt metaborate is blue.$II$. Diborane is prepared by the oxidation of sodium borohydride with iodine.$III$. In diborane,the oxidation state of hydrogen is $+1$.$IV$. Boric acid is a tribasic acid.