Consider the compounds,$BCl_3$ and $CCl_4$. How will they behave with water? Justify.
(N/A) $BCl_3$ is an electron-deficient molecule. The $B$ atom has an incomplete octet and accepts a lone pair of electrons from water,leading to hydrolysis to form boric acid:
$BCl_3 + 3 H_2O \rightarrow H_3BO_3 + 3 HCl$
On the other hand,$CCl_4$ is an electron-precise molecule. The $C$ atom has a complete octet and lacks vacant $d$-orbitals to expand its coordination number. Therefore,it cannot accept electrons from water,and $CCl_4$ does not undergo hydrolysis.
$BCl_3 + 3 H_2O \rightarrow H_3BO_3 + 3 HCl$
On the other hand,$CCl_4$ is an electron-precise molecule. The $C$ atom has a complete octet and lacks vacant $d$-orbitals to expand its coordination number. Therefore,it cannot accept electrons from water,and $CCl_4$ does not undergo hydrolysis.
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Similar Questions
Identify the incorrect statement about the group $13$ elements.
Match the following compounds in List-$I$ with their properties/names in List-$II$.
List-$I$ (Compound) List-$II$ (Property/Name/Structure) $A$. $H_3BO_3$ $1$. Dimeric form $B$. $AlCl_3$ $2$. Back bonding $C$. $B_3N_3H_6$ $3$. Hydrogen bonding $D$. $BF_3$ $4$. Inorganic benzene
| List-$I$ (Compound) | List-$II$ (Property/Name/Structure) |
|---|---|
| $A$. $H_3BO_3$ | $1$. Dimeric form |
| $B$. $AlCl_3$ | $2$. Back bonding |
| $C$. $B_3N_3H_6$ | $3$. Hydrogen bonding |
| $D$. $BF_3$ | $4$. Inorganic benzene |
The first ionization enthalpy values (in $kJ\, mol^{-1}$) of group $13$ elements are:
Element $B$ $Al$ $Ga$ $In$ $Tl$ Ionization Enthalpy $801$ $577$ $579$ $558$ $589$
How would you explain this deviation from the general trend?
| Element | $B$ | $Al$ | $Ga$ | $In$ | $Tl$ |
|---|---|---|---|---|---|
| Ionization Enthalpy | $801$ | $577$ | $579$ | $558$ | $589$ |
How would you explain this deviation from the general trend?
Difficult
View SolutionWhich of the following is known as inorganic benzene?
Medium
View SolutionExplain the following:
$(1)$ $BF_3$ does not hydrolyze.
$(2)$ Why does the element silicon not form a graphite-like structure,whereas carbon does?
$(1)$ $BF_3$ does not hydrolyze.
$(2)$ Why does the element silicon not form a graphite-like structure,whereas carbon does?
Difficult
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