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(D) The standard state of a substance is defined as its pure form at a pressure of $1 \ bar$ and a specified temperature (usually $298 \ K$).$\Delta_{

Vedclass · Accepted Answer

$\Delta_{f} H_{500}^{	heta}$ is zero for $O_{2(g)}$

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(D) The standard state of a substance is defined as its pure form at a pressure of $1 \ bar$ and a specified temperature (usually $298 \ K$).$\Delta_{f} H^{	heta}$ (standard enthalpy of formation) is defined as zero for elements in their most stable state at the specified temperature.For $O_{2(g)}$,which is the most stable form of oxygen,$\Delta_{f} H^{	heta} = 0$ at any specified temperature.Therefore,$\Delta_{f} H_{500}^{	heta}$ is zero for $O_{2(g)}$ is the correct statement.

The correct statement amongst the following is $:$

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