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(C) The electronic configuration of a chlorine atom $(Z=17)$ is $1s^2 2s^2 2p^6 3s^2 3p^5$.The unpaired electron is present in the $3p$ subshell.For t

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$3, 1, 1, \pm \frac{1}{2}$

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(C) The electronic configuration of a chlorine atom $(Z=17)$ is $1s^2 2s^2 2p^6 3s^2 3p^5$.The unpaired electron is present in the $3p$ subshell.For the $3p$ orbital: Principal quantum number $(n)$ = $3$,Azimuthal quantum number $(l)$ = $1$.The $3p^5$ configuration fills the orbitals as follows: $m_l = -1$ ($2$ electrons),$m_l = 0$ ($2$ electrons),$m_l = +1$ ($1$ electron).Thus,for the unpaired electron: $n=3$,$l=1$,$m_l=1$,and $m_s = \pm \frac{1}{2}$.

The correct set of quantum numbers for the unpaired electron of a chlorine atom is:

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The quantum numbers of four electrons are given below:
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