Difficult
The correct set of four quantum numbers for the valence electron of rubidium atom $(Z=37)$ is:
- A$n=5, l=0, m=0, s=+\frac{1}{2}$
- B$n=5, l=0, m=1, s=+\frac{1}{2}$
- C$n=5, l=1, m=0, s=+\frac{1}{2}$
- D$n=5, l=1, m=1, s=+\frac{1}{2}$
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