In the ground state of Cr,the number of elect | vedclass

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(A) The atomic number of $Cr$ is $24$. Its electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5$.For $l = 1$ (p-orbitals),we consider the $

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$12, 5$

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(A) The atomic number of $Cr$ is $24$. Its electronic configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5$.For $l = 1$ (p-orbitals),we consider the $2p$ and $3p$ subshells. The number of electrons is $6 + 6 = 12$.For $l = 2$ (d-orbitals),we consider the $3d$ subshell. The number of electrons is $5$.Therefore,the number of electrons with $l = 1$ and $l = 2$ are $12$ and $5$ respectively.

In the ground state of $Cr$,the number of electrons with $l = 1$ and $l = 2$ in its electronic configuration are respectively:

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