The correct order of the decreasing ionic rad | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.All the given species $(S^{2-}, Cl^{-}, K^{+}

Vedclass · Accepted Answer

$S^{2-} > Cl^{-} > K^{+} > Ca^{2+}$

Vedclass · Answer

(C) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.All the given species $(S^{2-}, Cl^{-}, K^{+}, Ca^{2+})$ have $18$ electrons.The atomic numbers are: $S (16), Cl (17), K (19), Ca (20)$.As the nuclear charge increases,the force of attraction between the nucleus and the electrons increases,which pulls the electron cloud closer to the nucleus,resulting in a smaller ionic radius.Therefore,the order of decreasing ionic radii is $S^{2-} > Cl^{-} > K^{+} > Ca^{2+}$.

$A$. Element	$B$. Atomic Radius $(pm)$
$A$. $Be$	$I$. $74$
$B$. $C$	$II$. $77$
$C$. $O$	$III$. $66$
$D$. $B$	$IV$. $88$
$E$. $N$	$V$. $111$

The correct order of the decreasing ionic radii among the following isoelectronic species is

Similar Questions

Which one is the correct order of the size of the iodine species?

Match the elements in Column-$A$ with their correct atomic radii in Column-$B$ (in $pm$).

$A$. Element $B$. Atomic Radius $(pm)$

$A$. $Be$ $I$. $74$

$B$. $C$ $II$. $77$

$C$. $O$ $III$. $66$

$D$. $B$ $IV$. $88$

$E$. $N$ $V$. $111$

The ionic radii of $F^{-}$ and $O^{2-}$ respectively are $1.33 \ \mathring{A}$ and $1.40 \ \mathring{A}$,while the covalent radius of $N$ is $0.74 \ \mathring{A}$. The correct statement for the ionic radius of $N^{3-}$ from the following is:

Arrange the following in the decreasing order of radius: $S^{2-}, P^{3-}, Cl^{-}, Ca^{2+}, Ar, K^{+}$

Which one of the following ions has the highest value of ionic radius?

Vedclass Test Series

Exam Paper Generator

Online Exam Module