Arrange the following in the decreasing order | vedclass

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Question

(A) All the given species $(S^{2-}, P^{3-}, Cl^{-}, Ca^{2+}, Ar, K^{+})$ are isoelectronic,meaning they all contain $18$ electrons.For isoelectronic s

Vedclass · Accepted Answer

$P^{3-} > S^{2-} > Cl^{-} > Ar > K^{+} > Ca^{2+}$

Vedclass · Answer

(A) All the given species $(S^{2-}, P^{3-}, Cl^{-}, Ca^{2+}, Ar, K^{+})$ are isoelectronic,meaning they all contain $18$ electrons.For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number,$Z$) increases.The atomic numbers are: $P (Z=15), S (Z=16), Cl (Z=17), Ar (Z=18), K (Z=19), Ca (Z=20)$.Since the number of electrons is constant $(18)$,the species with the lowest atomic number will have the weakest nuclear attraction for the electrons,resulting in the largest radius.Therefore,the decreasing order of radius is: $P^{3-} > S^{2-} > Cl^{-} > Ar > K^{+} > Ca^{2+}$.

Arrange the following in the decreasing order of radius: $S^{2-}, P^{3-}, Cl^{-}, Ca^{2+}, Ar, K^{+}$

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