The correct order of relative stability for t | vedclass

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(B) The stability of free radicals is determined by the resonance and inductive effects of the attached groups.$I$ is an ethyl radical $(CH_3CH_2^{\bu

Vedclass · Accepted Answer

$I < III < II$

Vedclass · Answer

(B) The stability of free radicals is determined by the resonance and inductive effects of the attached groups.$I$ is an ethyl radical $(CH_3CH_2^{\bullet})$,which is stabilized by hyperconjugation.$II$ is a radical with an amino group $(N(CH_3)_2)$ attached to the radical carbon. The lone pair on the nitrogen atom provides resonance stabilization through the $+M$ effect,which is very effective for radical stabilization.$III$ has both an amino group $(N(CH_3)_2)$ and an ester group $(COOEt)$ attached to the radical carbon. While the amino group provides strong resonance stabilization,the ester group is electron-withdrawing ($-I$ and $-M$ effects),which destabilizes the radical compared to $II$.Therefore,the stability order is $III < II < I$ is incorrect based on the provided options; the correct order is $I < II < III$ is also not quite right as $II$ is more stable than $I$ due to resonance. Comparing $II$ and $III$,$II$ is more stable than $III$ because the electron-withdrawing ester group in $III$ reduces the electron density on the radical carbon. Thus,the order is $I < III < II$.

The correct order of relative stability for the given free radicals is:

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