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(B) The reaction involves the abstraction of two chloride ions from the non-aromatic $7,8-dichlorocycloocta-1,3,5-triene$ (or similar derivative) by t

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(B) The reaction involves the abstraction of two chloride ions from the non-aromatic $7,8-dichlorocycloocta-1,3,5-triene$ (or similar derivative) by the Lewis acid $SbCl_5$.$SbCl_5$ acts as a strong chloride ion acceptor,forming the stable $SbCl_6^-$ anion.By removing two $Cl^-$ ions,the ring system forms a $cyclooctatetraenyl$ dication $(C_8H_8^{2+})$.This dication has $6$ $\pi$ electrons ($4n+2$ where $n=1$),making it aromatic according to $Huckel's$ rule.Therefore,the product $p$ is the aromatic $cyclooctatetraenyl$ dication associated with two $SbCl_6^-$ counterions.

$p$ will be

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