The correct order of rate of reaction toward | vedclass

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(A) The rate of nucleophilic addition reaction depends on the electrophilicity of the carbonyl carbon. $1$. Aldehydes are more reactive than ketones d

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$a > b > c > d > e$

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(A) The rate of nucleophilic addition reaction depends on the electrophilicity of the carbonyl carbon. $1$. Aldehydes are more reactive than ketones due to less steric hindrance and electronic factors. $2$. Electron-withdrawing groups (like $-NO_2$) increase the electrophilicity of the carbonyl carbon,while electron-donating groups (like $-OMe$) decrease it. $3$. Comparing the given compounds: $(a)$ $p-NO_2-C_6H_4-CHO$: Contains a strong electron-withdrawing group $(-NO_2)$,making it the most reactive. $(b)$ $C_6H_5-CHO$: Benzaldehyde. $(c)$ $p-OMe-C_6H_4-CHO$: Contains an electron-donating group $(-OMe)$,making it less reactive than benzaldehyde. $(d)$ $CH_3-CO-CH_2CH_3$: Aliphatic ketone,more reactive than aromatic ketone. $(e)$ $C_6H_5-CO-C_6H_5$: Benzophenone,least reactive due to steric hindrance and resonance stabilization of the carbonyl group by two phenyl rings. Thus,the order is $a > b > c > d > e$.

Column $I$	Column $II$
$A$. $C_6H_5CHO$	$p$. gives precipitate with $2, 4-$dinitrophenylhydrazine
$B$. $CH_3C \equiv CH$	$q$. gives precipitate with $AgNO_3$
$C$. $CN^{-}$	$r$. is a nucleophile
$D$. $I^{-}$	$s$. is involved in cyanohydrin formation

The correct order of rate of reaction toward nucleophilic addition reaction for the following compounds is:
$(a)$ $p-NO_2-C_6H_4-CHO$
$(b)$ $C_6H_5-CHO$
$(c)$ $p-OMe-C_6H_4-CHO$
$(d)$ $CH_3-CO-CH_2CH_3$
$(e)$ $C_6H_5-CO-C_6H_5$

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The correct order of rate of reaction toward nucleophilic addition reaction for the following compounds is:$(a)$ $p-NO_2-C_6H_4-CHO$$(b)$ $C_6H_5-CHO$$(c)$ $p-OMe-C_6H_4-CHO$$(d)$ $CH_3-CO-CH_2CH_3$$(e)$ $C_6H_5-CO-C_6H_5$